MATEMATİK I

Intersection of this set with C is

(A ∪ B) ∩ C = {c, d, g}.

Then, s(M ∪ S) = 250-17 = 233.

Using the formula (M ∪ S) = s(M) + s(S) – s(M ∩ S),

we have s(M ∩ T) = 233 = 153 + 110 - x, where x is the required number.

Then we find that x = 153 + 110 - 233.

Thus, x equals to 30.

2^-1 is 1/2¹ which equals to 1/2;

3^-1 is 1/3¹ which equals to 1/3; and 3^-2 is 1/3² which equals to 1/9,

what we have in hand is ( (1/2) + (1/3) ) / (1/9). (1/2) + (1/3) equals to 11/18,

and if we divide it by 1/9, this equals to 11/2.

When we do the operation 3^-2 . 3² , we find 3^-2+2 which equals to 3⁰. 3⁰ equals to 1.

Then we find that

7/12 =35/60,

3/5 = 36/60,

11/15 = 44/60,

14/20 = 42/60, and

23/30 = 46/60.

The greatest number among these is, therefore, 23/30.

|b – a| = b – a since a < b

and

|a – c| = c - a since a < c.

Therefore |b – a| + |a – c| = b – a + c – a  = -2a + b + c.

Then, (2, 8) \ [0, 7) is the required result.

It is [7, 8), and D is the correct answer.

Then, C  \ (A ∪ B) must be an empty set.

F = {x| x is a student who taking Flute course}

The number of students taking Piano or Flute courses is

s(P ∪ F) = s(P) + s(F) –s(P ∩ F).

s(P ∪ F) = 45 + 22 – 15 =  67 – 15 = 52

Additionally, 17 students  are taking neither Piano, nor Flute courses. Therefore, the total number of students is 52 + 17 = 69.

Correct answer is C.

x = max {2 / 5, 1 / 4, 3 / 8, 3 / 10, 7 / 16}

= max {32/80, 20/80, 30/80, 24/80, 35/80} 

= 35/80 = 7 / 16.

pg. 12. Correct answer is E.

B = [3, 8) = {x| x ∈ R  and 3 ≤ x < 8},

A ∪ B = {x| x ∈ A or x ∉ B}. Then A ∪ B= {x| -4 < x < 8 } = (-4, 8)

  Correct answer is B.

 A ∩ B ∩ C = {c}

Correct answer is C

a > b then |a – b| =  a - b 

c > a then  |c – a| = c - a 

Then  |b – c| + |a – b| + |c – a| = -b + c + a - b + c - a

= -2b + 2c

= 2c - 2b 

Answer is A.